The diagonal of the parallelogram ABCD is perpendicular to the AD side.

The diagonal of the parallelogram ABCD is perpendicular to the AD side. find the area of the parallelogram ABCD if AB = 12 cm angle B = 41 degrees sin41 ^ = 0.6561 cos 41 ^ = 0.7547

Consider a right-angled triangle ABC, which, by condition, has an angle C of a straight line, and an angle B = 41.

Then Sin41 = AC / AB.

AC = AB * Sin41 = 12 * 0.6561 = 7.8732 cm.

Cos410 = BC / AB.

BC = AB * Cos41 = 12 * 0.7547 = 9.0564 cm.

Then the area of the parallelogram is:

Savsd = AC * BC = 7.8732 * 9.9564 = 71.3 cm2.

Answer: The area of the parallelogram is 71.3 cm2.



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