The diagonal of the rectangle intersect at an angle of 20 °. Find the corners that form a diagonal

The diagonal of the rectangle intersect at an angle of 20 °. Find the corners that form a diagonal with the sides of the rectangle.

The diagonals of the rectangle, at the point of their intersection, are divided in half, therefore, ОА = ОD = ОВ = ОВ.
Then the triangles AOD, AOB, COD, COD are isosceles and their angles at the base are equal.
Angle ОАВ = ОВА = (180 – 20) / 2 = 80.
Angle ABC = 90, then angle CDO = 90 – OBA = 90 – 80 = 10.
Answer: The diagonals form angles 10 and 80 with the sides.



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