The diagonal of the rectangle makes an angle of 58 with its side. Find the angle between the diagonals of the rectangle.

The diagonals of the rectangle, at the points of their intersection, are divided in half, therefore, ОА = ОD = ОВ = ОВ.

Then the triangles AOD, AOB, COB, COD are isosceles and their angles at the base are equal.

The angle OAB = OBA = 58, then the angle AOB = 180 – 58 – 58 = 64.

The angle BOD is expanded and is equal to 180, then the angle AOD = BOD – AOB = 180 – 64 = 116.

Answer: The angles between the diagonals are 64 and 116.



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