The diagonal of the rectangle makes an angle of 63 ° on one of its sides.

The diagonal of the rectangle makes an angle of 63 ° on one of its sides. Find an acute angle between the diagonals of this rectangle.

The diagonals of the rectangle, at the point of their intersection, are divided in half, therefore, ОА = ОD = ОВ = ОВ.

Then the triangles AOD, AOB, COB, COD are isosceles and their angles at the base are equal.

The angle OAB = OBA = 63, then the angle AOB = 180 – 63 – 63 = 54.

Answer: The acute angle between the diagonals is 54.



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