The diagonal of the trapezoid forms an angle of 42 degrees with the smaller base. find the value of the angle that this diagonal forms with a large base.
The angle ACB, formed by the diagonal of the trapezoid and its small base, is equal to the angle formed by the same diagonal and the large base, like criss-crossing Uds at the intersection of parallel straight lines AD and BC of the secant line AC. Therefore, the angle CAD = ACB = 42.
Answer: Angle CAD = 42.
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