The diagonals of a parallelogram are 6√2 and 8√2. Find the sum of the squares of all its sides.
| November 20, 2020 | education
The sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of all its sides
(6 x√2) 2+ (8 x√2) 2 = 72 + 128 = 200
Sum of squares of diagonals = 200
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