The diagonals of parallelogram ABCD meet at point O. Prove that triangles BCO and DCO have equal areas.
| February 6, 2021 | education
Let us construct the perpendicular CH to the ВD diagonal.
CH is the total height for the triangles ВCO and DСO. Since AВСD is a parallelogram, its diagonals at the point of intersection O are divided in half, then OВ = OD.
Svso = ОВ * СН.
Sdso = OD * CH.
And since OB = OD, then Svso = Sdso, which was required to prove.
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