The diagonals of rectangle ABCD intersect at point O, angle ABO is 36. Find angle AOB
| December 17, 2020 | education
Since the triangle AOB is isosceles (since the diagonals in the rectangle are equal and the intersection point is halved). Then the angle ABO is equal to the angle BAO and is equal to 36 degrees, as are the corners at the base.
The sum of the angles of a triangle is 180 degrees, then the sum of the angles ABO + BAO + AOB = 180 degrees
Hence the angle AOB = 108 degrees
Answer: 108 degrees
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