The diagonals of the parallelogram ABCD intersect at point O. Find the difference between the perimeters

The diagonals of the parallelogram ABCD intersect at point O. Find the difference between the perimeters of the triangles AOB and BOS if CD = 11cm and AD = 6cm.

Perimeter AOB – Perimeter BOC = AO + OB + AB- (BO + OC + BC) = AO + OB + AB-BO-OC-BC = AO + AB-OC-BC = AB-BC = 11-6 = 5
Answer: the difference in perimeters is 5



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