The diagonals of the quadrilateral ABCD meet at point O. AC = 2 dm. AO = 10cm BD = 1.5m.

The diagonals of the quadrilateral ABCD meet at point O. AC = 2 dm. AO = 10cm BD = 1.5m. BО = 7 cm. Find out is the ABCD parallelogram.

Given:
quadrilateral ABCD,
ВD and АС – diagonals,
point O – the point of intersection of the diagonals BD and AC,
AC = 2 dm,
AO = 10 cm,
BD = 1.5m,
BО = 7 cm.
Find out is the ABCD parallelogram -?
Decision:
Consider a quadrilateral ABCD. In a parallelogram, the intersection point is halved. Let’s check if this is true in our quadrilateral ABCD.
OS = AC – AO;
AC = 2 dm = 20 cm;
OС = 20 – 10;
OС = 10 cm.
Therefore: AO = OС = 10 cm;
OD = BD – BO;
BD = 1.5 m = 150 cm;
OD = 150 – 7;
OD = 143.
Then the quadrilateral ABCD is not a parallelogram.
Answer: it is not.



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