The diagonals of the rectangle ABCD crossed at point O ABO = 36 deg. find AOD.

And so, consider BAO and ABO:

BAO = ABO = 36 º

Further, the angle OAD (90º) and ABO (36º):

ОАD – АBО = 90 º -36 º

It follows that the angles OAD and ADO are equal, i.e. at 54 º:

ОАD = АDО = 54 º

When we learned that the OAD angle is 54 º, we get:

AOD = 180º – OAD – ADO = 180 º – 56 º- 56 º = 68 º
The AOD angle is 68 º.



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