The diagonals of the rhombus are 14 cm and 48 cm. Find the side of the rhombus.

Because the diagonals of the rhombus are perpendicular and the intersection point is halved, then:
AO = ½ AC = ½ * 14 = 7 (cm);
BO = ½ BD = ½ * 48 = 24 (cm).
ABO triangle – rectangular.
By the Pythagorean theorem, we find the hypotenuse of the triangle (the side of the rhombus):
AB2 = BO2 + AO2 = 576 + 49 = 625;
AB = 25 (cm).
Answer: the side of the rhombus is 25 cm.



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