The diagonals of the rhombus are 5 cm and 5√3 cm find the corners of the rhombus.

We denote the given rhombus by the condition ABCD, the diagonals are equal:
AC = 10√3 (cm);
BD = 10 (cm).
Point O is the point of intersection of the diagonals. It divides the diagonals in half.
In the right-angled triangle AOB, we find the hypotenuse AB (by the Pythagorean theorem):
AB = √ (AO² + BO²) = √ (75 + 25) = √100 = 10 (cm).
Leg VO = 5 cm – half of the hypotenuse AB, which means that the angle ABO = 30 °, and the angle ABO = 90 ° – 30 ° = 60 °.
Accordingly, in a rhombus, the angle A = 2 * ∠ VAO = 60 °, the angle B = 2 * ∠ ABO = 120 °.
Answer: the angles of the rhombus are 60 °, 60 °, 120 °, 120 °.