The diameter AB and chords AC and CD were drawn in a circle so that AC = 12cm, ∠BAC = 30 °,

The diameter AB and chords AC and CD were drawn in a circle so that AC = 12cm, ∠BAC = 30 °, AB⊥CD. Find the length of the chord CD.

Since the chord CD is perpendicular to the diameter of the circle, the ACN triangle is rectangular.

The CH leg lies opposite an angle of 30, then its length is equal to half the length of the AC hypotenuse.

CH = AC / 2 = 6 cm.

If the chord is perpendicular to the diameter of the circle, then the diameter divides the chord in half, then CH = DH = 6 cm, CD = CH + DH = 6 + 6 = 12 cm.

Answer: The length of the chord CD is 12 cm.



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