The diameter AB and the chord CD not crossing this diameter are drawn in the circle, while the chords AC and BD

The diameter AB and the chord CD not crossing this diameter are drawn in the circle, while the chords AC and BD also do not intersect, the angle ABC is 22 degrees find the degree measure of the angle CDB

The desired angle CDB is the sum of the angles CDA and ADB. The CDA is inscribed and rests on the AC arc. The inscribed angle CBA known to us, which is equal to 22˚, rests on the same arc. By the property of inscribed angles based on one arc:
∟CDA = ∟ CBA = 22˚.
Angle ADB rests on the diameter (which contracts the arc 180˚) and, by the property of inscribed angles, is equal to half of the arc on which it rests, i.e.
∟ADB = 180˚ / 2 = 90˚.
∟CDB = ∟CDA + ∟ADB = 22˚ + 90˚ = 112˚.
Answer: The CDB angle is 112˚.