The diameter of the ball is 25 cm. On its surface, point A and a circle are given, all points of which are removed

| September 14, 2021 | education

The diameter of the ball is 25 cm. On its surface, point A and a circle are given, all points of which are removed (in a straight line) from A by 15 cm. Find the radius of this circle.

Consider a triangle ABO, in which OB and OA are the radii of the ball, and are equal to half of the AC, and the side AB is, by condition, 15 cm.

Let us determine the area of the triangle through its sides and semiperimeter.

p = (AB + AO + BO) / 2 = (15 + 12.5 + 12.5) / 2 = 20 cm.

Savo = √ (p * (p – AO) * (p – BO) * (p – AB) = √ (20 * (20 – 12.5) * (20 – 12.5) * (20 – 15) = √5625 = 75 cm2.

Let’s define the area of the same triangle through the height and base of the triangle.

Savo = AO * BO1 / 2 = 6.25 * BO1.

75 = 6.25 * BO1.

BO1 = 75 / 6.25 = 12 cm.

Answer: The radius of the circle is 12 cm.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.