The diameter of the cell nucleus is 8 μm. Determine the size of its image in a microscope if the objective lens is 100x and the eyepiece is 6x.

d1 = 8 microns = 8 * 10 ^ -6 m.
nob = 100.
nok = 6.
d2 -?
The size of the image in the eyepiece of the microscope d2 is determined by the formula: d2 = N * d1, where N is the magnification of the microscope, d1 is the size of the object that I consider through the microscope.
The magnification of the microscope N is determined by the product of the objective magnification nob and the eyepiece magnification nok: N = nob * nok.
d2 = nrev * nok * d.
d2 = 100 * 6 * 8 * 10 ^ -6 m = 4800 * 10 ^ -6 m = 0.0048 m.
Answer: the size of the image of the object in the microscope is d2 = 0.0048 m.