The diameter of the log is 12 cm. Is it possible to cut a square beam with a side of 10 cm from this log?

Let’s draw a square inscribed in a circle with a diameter of 12 cm.The diagonals of the square intersect at right angles, then the angle AOB = 90, and the triangle AOB is rectangular, with the legs AO and OD equal to the radius of the circle (logs).

AO = DO = AC / 2 = 12/2 = 6 cm.

Then, by the Pythagorean theorem, we define the hypotenuse of HELL, which is the side of the square.

AD ^ 2 = AO ^ 2 + DO ^ 2 = 36 + 36 = 72.

AD = √72 = 6 * √2 ≈ 8.49 cm.

8.49 <10, therefore, a beam with a side of 10 cm cannot be cut from a log with a diameter of 12 cm.

Answer: You can’t.