The diesel engine of the car produces work of 191.36 kJ. How much fuel does it consume during

The diesel engine of the car produces work of 191.36 kJ. How much fuel does it consume during operation if its efficiency is 35%?

Data: Ap (work done by the engine) = 191.36 kJ (191.36 * 10 ^ 3 J); η (motor efficiency) = 35% (0.35).

Reference values: qd (specific heat of combustion of diesel fuel) = 47.2 * 10 ^ 6 J / kg.

To determine the mass of diesel fuel consumed by the engine, we use the formula: η = Ap / Q = Ap / (qd * m), whence m = Ap / (qd * η).

Let’s calculate: m = 191.36 * 10 ^ 3 / (47.2 * 10 ^ 6 * 0.35) = 0.0116 kg = 11.6 g.

Answer: The diesel engine has consumed 11.6 g of diesel fuel.