The difference between the angles adjacent to one side of the parallelogram is 36. Find the angles of the parallelogram.

By the property of a parallelogram, the sum of the adjacent angles of a parallelogram is 180.

Let the value of the angle BAC = X0, then, by condition, the angle ABC = (X + 36) 0.

The sum of the angles ABC + BAC = 180.

(X + 36) + X = 180.

2 * X = 180 – 36 = 144.

X = 72.

Angle BAC = BCD = 72.

Ugo ABC = ADC = 72 + 36 = 108.

Answer: The angles of the parallelogram are 72 and 108.



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