The difference between the angles adjacent to one side of the parallelogram is 48

The difference between the angles adjacent to one side of the parallelogram is 48 degrees. Find the smaller angle of the parallelogram in degrees.

Given:
Parallelogram;
∠1-∠2 = 48 °;
∠2 =?
Decision:
The angles adjacent to one side of the parallelogram are internal one-sided. The sum of the inner one-sided angles is 180 °. Then:
∠1 + ∠2 = 180 ° (*);
∠1-∠2 = 48 ° (**).
Subtract (**) from (*), then:
∠1 + ∠2- (∠1-∠2) = 180-48;
∠1 + ∠2-∠1 + ∠2) = 132;
2 * ∠2 = 132;
∠2 = 132: 2;
∠2 = 66 °;
Answer: 66 °