The difference between two one-sided angles at the intersection of two parallel secant lines is 50 °. Find these corners.

Let X be one one-sided corner and Y another one-sided corner and X> Y.
Then we write the condition of the problem in the form of an equation:
X – Y = 50
It is known that the sum of two one-sided angles at the intersection of two parallel straight lines is 180 degrees, i.e .:
X + Y = 180
X = 180 – Y
Substitute X into the first equation:
180 – Y – Y = 50
-2 * Y = -130
Y = 65
X = 180 – Y = 180 – 65 = 115

Answer: 65 and 115 degrees.