The dimension of an isosceles triangle is 48 cm and one of its sides is 6 cm larger than the other.

The dimension of an isosceles triangle is 48 cm and one of its sides is 6 cm larger than the other. Find the side of the triangle.

1 case.

Let’s say that the base of an isosceles triangle is x cm.

Since the side is 6 cm larger, its length will be: x + 6 cm.

Since the sides of the triangle are equal to each other, the perimeter of the figure will be:

x + x + 6 + x + 6 = 48.

3 * x = 48 – 12.

3 * x = 36.

x = 36/3 = 12 cm (base).

x + 6 = 12 + 6 = 18 cm (side).

2 case.

Let’s say the side is x cm.

Since the base is 6 cm larger, its length will be: x + 6 cm.

The perimeter of the triangle will be:

x + x + x + 6 = 48.

3 * x = 48 – 6.

3 * x = 42.

x = 42/3 = 14 cm (side).

x + 6 = 14 + 6 = 20 cm (base).