The dimensions of the bars are the same (glass lead steel brick). Which one has the greatest mass? The smallest?

V1 = V2 = V3 = V4 = V – the sizes of the bars are the same;

ro1 = 2500 kg / m ^ 3 – glass density;

ro2 = 11300 kg / m ^ 3 – lead density;

ro3 = 7800 kg / m ^ 3 – steel density;

ro4 = 1450 kg / m ^ 3 – brick density.

It is required to determine the body with the largest and smallest mass.

The mass of the first body will be equal to: m1 = ro1 * V1 = 2500 * V1 = 2500 * V;

The mass of the second body will be equal to: m2 = ro2 * V2 = 11300 * V2 = 11300 * V;

The mass of the third body will be equal to: m3 = ro3 * V3 = 7800 * V3 = 7800 * V;

The mass of the fourth body will be equal to: m4 = ro4 * V4 = 1450 * V4 = 1450 * V.

Since 11300 * V> 7800 * V> 2500 * V> 1450 * V, the body of lead will have the greatest mass, and the body of brick will have the smallest mass.

Answer: the largest mass is in the lead bar, the smallest – in the brick bar.