The displacement of the atomic icebreaker arktika is 234600 kN. What is the volume of its underwater part?

In order for the ship to stay on the water, it is necessary that the buoyancy force of Archimedes be equal to its weight.
Since the displacement, by definition, is the weight of the water displaced by the ship, then, using the formula of Archimedes’ law, we immediately find the volume of the underwater part of the ship.
F (a) – Archimedes force equal to the weight of the displaced fluid
g – acceleration of gravity 9.8 m / s ^ 2
p – density of water 1000 kg / m ^ 3
V – the volume of displaced water, of course, equal to the volume of the underwater part of the ship.
F (a) = gpV; V = F (a) / gp
234600000 / 9.8 * 1000 = 23938.8
Answer: the volume is 23939 m ^ 3