The distance between cities A and B is 555 km. A car leaves town A in the direction of town B at a speed

The distance between cities A and B is 555 km. A car leaves town A in the direction of town B at a speed of 90 km / h. After 30 minutes, a car leaves town B towards him at a constant speed. It is known that a car from city B in 3 hours will meet a car from city A. How fast was the car from city B moving?

1. According to the problem statement, the distance between cities is 555 km.

The speed of the car that left the city A is 90 km / h.

It is known that the car from hunger B left after 30 minutes or 0.5 hours.

Determine what the distance between the cars was at the time of start.

555 – 90 * 0.5 = 555 – 45 = 510 km.

2. The problem says that 3 hours have passed before the meeting.

Let’s calculate the speed of approach.

510/3 = 170 km / h.

3. Now you can find the speed of the second second car.

170 – 90 = 80 km / h.

Answer: A car from city B was traveling at a speed of 80 km / h.



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