The distance between motorcycles moving towards each other is 1500m.

| April 28, 2021 | education

The distance between motorcycles moving towards each other is 1500m. Determine where and when they will meet, if the speed of the first is 40 km / h, the author is 36 km / h.

S = 1500 m.

V1 = 40 km / h = 11.1 m / s.

V2 = 36 km / h = 10 m / s.

tvs -?

Sвс -?

Let us express the paths S1 of the first and S2 of the second motorcyclist to the meeting using the formulas: S1 = V1 * tвс, S2 = V2 * tвс, where V1, V2 are the speed of the first and second motorcyclists.

The distance between the motorcyclists at the beginning of the movement S is expressed by the sum: S = S1 + S2.

S = V1 * tvs + V2 * tvs = (V1 + V2) * tvs.

The time of movement of motorcyclists before the meeting tвс will be determined by the formula: tвс = S / (V1 + V2).

tvs = 1500 m / (11.1 m / s + 10 m / s) = 71 s.

Svs = V1 * ts.

Sws = 11.1 m / s * 71 s = 788.1 m.

Answer: motorcyclists will meet in time tвс = 71 s, at a distance Sвс = 788.1 m from the place of departure of the first motorcyclist.



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