The distance between points A and B is 114 km. At 6 o’clock a truck left point A for B, and at 6:45

The distance between points A and B is 114 km. At 6 o’clock a truck left point A for B, and at 6:45 am a bus came out to meet it at a speed of 8 km / h more than the speed of the truck. The meeting took place at 07:30. Find truck and bus speeds.

Let’s denote the speed of the truck by the letter x.

The truck left at 6 o’clock, and met the bus at 7:30, which means it was on the way for 1 hour 30 minutes or 1.5 hours.

The bus speed is 8 km / h higher than that of a truck, that is, x + 8 km / h.

The bus started moving at 6 hours 45 minutes, which means that until the meeting was on the way for 45 minutes or 0.75 hours.

Since the cars met at 7:30, it means that they drove 114 km towards each other. We get the equation:

1.5 * x + 0.75 * (x + 8) = 114,

1.5 * x + 0.75 * x + 6 = 114,

2.25 * x = 108,

x = 48 (km / h) – truck speed,

48 + 8 = 56 (km / h) – bus speed.