The distance between points A and B is 156 km. A cyclist goes from A to B. After 2 hours

| May 5, 2021 | education

The distance between points A and B is 156 km. A cyclist goes from A to B. After 2 hours, another cyclist sets out to meet him at a speed 4 km / h higher than the speed of the first cyclist. The meeting took place at a distance of 72 km from V. Find the sum of the speeds of these cyclists.

х km per hour – the speed of the first cyclist,

х + 4 km per hour – speed of the second cyclist,

72 / (x + 4) hours – the second cyclist was riding,

(156 – 72) / х = 84 / х hours – the first cyclist was riding.

Let’s make the equation:

84 / x – 2 = 72 / (x + 4);

We simplify, we give similar:

2x ^ 2 – 4x – 336 = 0.

x1 = -12 (speed cannot be negative),

x2 = 14 km per hour the speed of the first cyclist,

14 + 4 = 18 km per hour the speed of the second,

14 + 18 = 32 km per hour the sum of the speeds of the two cyclists.



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