# The distance between points A and B is 17 km. A cyclist set out from A to B at a speed of 12 km / h

The distance between points A and B is 17 km. A cyclist set out from A to B at a speed of 12 km / h. At the same time, a pedestrian left A to B at a speed of 5 km / h. The cyclist reached B, turned and drove back at the same speed. How many hours after the start of the movement will they meet?

Let’s calculate the time it takes for the cyclist to reach point “B”.

17/12 ≈ 1.4166 hours (this is 1 hour 25 minutes).

We find out the distance that a pedestrian will walk during the time it takes a cyclist to reach point “B”.

1.4166 * 5 = 7.0833 km.

Now, when the cyclist turns around and goes towards the pedestrian, they approach each other at a speed of 12 + 5 = 17 km / h.

Divide the remainder of the distance by the approach speed:

(17 – 7.0833) / 17 ≈ 0.5833 hours (this is exactly 35 minutes).

They will meet in 2 hours.

01:25 + 00:35 = 02:00 h.

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