# The distance between points A and B is 17 km. A cyclist set out from A to B at a speed of 12 km / h

**The distance between points A and B is 17 km. A cyclist set out from A to B at a speed of 12 km / h. At the same time, a pedestrian left A to B at a speed of 5 km / h. The cyclist reached B, turned and drove back at the same speed. How many hours after the start of the movement will they meet?**

Let’s calculate the time it takes for the cyclist to reach point “B”.

17/12 ≈ 1.4166 hours (this is 1 hour 25 minutes).

We find out the distance that a pedestrian will walk during the time it takes a cyclist to reach point “B”.

1.4166 * 5 = 7.0833 km.

Now, when the cyclist turns around and goes towards the pedestrian, they approach each other at a speed of 12 + 5 = 17 km / h.

Divide the remainder of the distance by the approach speed:

(17 – 7.0833) / 17 ≈ 0.5833 hours (this is exactly 35 minutes).

They will meet in 2 hours.

01:25 + 00:35 = 02:00 h.