The distance between points A and B is 65 km. A pedestrian left point A to point B at a speed of 5 km / h

| January 9, 2021 | education

The distance between points A and B is 65 km. A pedestrian left point A to point B at a speed of 5 km / h, and an hour later a cyclist left point B to point A at a speed of 15 km / h. How many hours after leaving the cyclist will meet the pedestrian? Solve using an equation.

1) Calculate how far a pedestrian will travel to the cyclist exit:
5 * 1 = 5 km;
2) Calculate how far a pedestrian and a cyclist will travel together:
65 – 5 = 60 km;
3) Let the distance traveled by the pedestrian before the meeting is x km, then the distance of the cyclist is (60 – x) km;
4) Using the formula for calculating the time, draw up an equation and solve it:
t = S / v;
x / 5 = (60 – x) / 15;
3x = 60 – x;
4x = 60;
x = 15;
5) Calculate the time after which the cyclist will meet the pedestrian:
15 * 5 = 3 hours
Answer: In 3 hours the cyclist will meet the pedestrian.



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