The distance between the charges q1 = 1nC and q2 = 6.7 nC is equal to r1 = 10cm.
| February 19, 2021 | education
The distance between the charges q1 = 1nC and q2 = 6.7 nC is equal to r1 = 10cm. What work must be done to transfer the second charge to the distance r2 = 1m of the first charge.
To solve the problem, let’s apply the formula:
A = Kq1q2 (1 / r1 – 1 / r2).
But first of all, we start by performing a condition analysis.
It says that the distance between the charges q1 = 1 nC and q2 = 6.7 nC is equal to r1 = 10 cm. It is also known that the second charge is transferred at a distance r2 = 1m from the first charge.
The beginning has enough data to calculate the value of the work that will be done.
Substitute the values and find:
A = 9 * 10 ^ 9 * 10 ^ -9 * 6.7 * 10 ^ -9 (1 / 0.1 – 1/1) = 60.3 * 10 ^ -9 (10 – 1) = 542.7 * 10 ^ -9 J.
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