The distance between the points of intersection of the graphs of the functions y = 2x + 2 and y = 3x-1 with the y-axis is equal to?

Let us find the point of intersection of the function y = 2x + 2 with the ordinate axis, i.e. with OU axis. All points of the OY axis have an abscissa equal to 0, we substitute x = 0 into the equation of the function:
y = 2 * 0 + 2 = 2.

The intersection point of the straight line y = 2x + 2 with the ordinate has coordinates (0; 2).

Let us find the point of intersection of the function y = 3x – 1 with the ordinate axis, i.e. with OU axis. All points of the OY axis have an abscissa equal to 0, we substitute x = 0 into the equation of the function:
y = 3 * 0 – 1 = -1.

The point of intersection of the straight line y = 3x – 1 with the ordinate has coordinates (0; -1).

Find the distance between points A (0; 2) and C (0; -1). The coordinates of the segment AC (0; -3).
L ^ 2 = AC ^ 2 = 0 + 9 = 9,

L = 3.

Answer: the distance is 3.



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