# The distance between the two cities is 60 km. The first half of this path, the cyclist traveled at a speed of 30 km / h

The distance between the two cities is 60 km. The first half of this path, the cyclist traveled at a speed of 30 km / h, and the second 20 km / h. What is the average speed of his movement along the entire path

Initial data: S (distance between cities) = 60 km; S1 (first half of the trip) = S2 (second half of the trip) = 0.5S = 0.5 * 60 = 30 km; V1 (speed on the first half of the journey) = 30 km / h; V2 (speed in the second half of the journey) = 20 km / h.

Average speed of a cyclist along the way:

Vav. = Stot. / ttot. = Stot. / (t1 + t2) = Stot. / (S1 / V1 + S2 / V2).

Let’s perform the calculation:

Vav. = 60 / (30/30 + 30/20) = 60 / 2.5 = 24 km / h.

Answer: The average speed of a cyclist along the entire route was 24 km / h.

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