The distance between two charges 6 nC and 10 nC is 3 centimeters. Find the force by which they act on each other.

Initial data: q1 (value of the first charge) = 6 nC = 6 * 10 ^ -9 C; q2 (value of the second charge) = 10 nC = 10 * 10 ^ -9 C; R (distance between given charges) = 3 cm = 0.03 m.

Constants: k (coefficient of proportionality, air) = 9 * 10 ^ 9 N * m ^ 2 / Kl ^ 2.

The force with which the charges act on each other can be determined by the formula: F = k * q1 * q2 / R ^ 2.

Let’s calculate: F = 9 * 10 ^ 9 * 6 * 10 ^ -9 * 10 * 10 ^ -9 / 0.03 ^ 2 = 0.0006 H = 0.6 mN.

Answer: The charges act on each other with a force of 0.6 mN.



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