The distance between two nearest crests of a wave in the sea is 10m. What is the frequency of vibration

The distance between two nearest crests of a wave in the sea is 10m. What is the frequency of vibration of water particles if the speed of waves is 4ms. What is the period of vibration

The wavelength λ, the velocity of propagation of the wave v and the frequency of oscillations of the particles in it ν are related by the formula: v = λ · ν. We get:

ν = v: λ.

It is known from the problem statement that the distance between the two nearest wave crests in the sea is λ = 10 m, the wave velocity is v = 4 m / s. Then the vibration frequency of water particles will be:

ν = 4 m / s: 10 m;

ν = 0.4 Hz.

The oscillation period of the particle T is related to the oscillation frequency ν by the formula:

T = 1: ν.

Means:

T = 1: 0.4 Hz;

T = 2.5 s.

Answer: the vibration frequency of water particles is 0.4 Hz; the oscillation period is 2.5 s.