The distance from the point of intersection of the diagonals of the rectangle to the larger

The distance from the point of intersection of the diagonals of the rectangle to the larger side is 2.5 cm. Find the smaller side of the rectangle.

Given:
rectangle ABCE,
AC and BE are the diagonals of the rectangle,
О – the point of intersection of the diagonals AC and BE,
OK – the distance from the point of intersection of the diagonals to the larger side of the aircraft,
OK = 2.5 centimeters.
Find the smaller side of the rectangle, that is, AB -?
Decision:
Consider a rectangle ABCE. Its opposite sides and diagonals are equal and the intersection point is divided in half. Then triangle BOC = triangle AOE on three sides. The KO segment is the height of the BOC triangle. Let’s omit the height of OH in the AOE triangle. Then KO = OH.
Therefore KH = 2 * 2.5;
KH = 5 centimeters.
Segment KH = AB = 5 centimeters.
Answer: 5 centimeters.