The distance traveled by the end of the 5 cm long second hand in 15 seconds is equal to ..

Problem data: R (length of a given second hand, radius of a circle) = 5 cm (in SI R = 0.05 m); t (time of movement of the second hand) = 15 s (therefore, n (number of revolutions) = 0.25 revolutions).

The path that this second hand will take in 15 seconds is determined by the formula: S = V * t = 2 * Π * R * ν * t = 2 * Π * R * (n / t) * t = 2 * Π * R * n.

Let’s perform the calculation: S = 2 * 3.14 * 0.05 * 0.25 = 0.0785 m (7.85 cm).

Answer: The end of this second hand has traveled a distance of 7.85 cm.