The diver descends into the sea to a depth of 90 m. Determine the water pressure at this depth.

The diver descends into the sea to a depth of 90 m. Determine the water pressure at this depth. The density of seawater is 1030 kg / m3.

h = 90 m.
ρ = 1030 kg / m ^ 3.
g = 9.8 m / s ^ 2.
P -?
The hydrostatic pressure of the liquid at the bottom is determined by the formula: P = ρ * g * h. Where ρ is the density of the fluid, g is the acceleration of gravity, h is the height of the fluid, in our case the depth.
P = 1030 kg / m ^ 3 * 9.8 m / s ^ 2 * 90 m = 908460 Pa.
Answer: the water pressure at a depth of h = 90 meters is P = 908460 Pa.