The dry-cargo motor ship can take on board no more than 120 grit blocks of 120 in size multiplied

The dry-cargo motor ship can take on board no more than 120 grit blocks of 120 in size multiplied by 250 and multiplied by 400 cm each. What is the total mass of the current load?

Given:

a = 120 centimeters = 1.2 meters;

b = 250 centimeters = 2.5 meters;

c = 400 centimeters = 4 meters – the size of the granite blocks;

n = 120 – the number of granite blocks that the bulk carrier can accommodate;

ro = 2600 kg / m ^ 3 – density of granite.

It is required to determine the total mass of the cargo M (kilogram).

Let’s find the volume of one granite block:

V = a * b * c = 1.2 * 2.5 * 4 = 1.2 * 10 = 12 m ^ 3.

Then the mass of one granite block is:

m = V * ro = 12 * 2600 = 31200 kilograms.

Total weight of cargo:

M = n * m = 120 * 31200 = 3744000 kilograms = 3744 tons.

Answer: the total weight of the cargo is 3744 tons.