The dynamometer spring under the action of a force of 4 N lengthened by 5 mm.
| May 17, 2021 | education
The dynamometer spring under the action of a force of 4 N lengthened by 5 mm. What is the stiffness of the dynamometer spring?
To determine the required spring stiffness of the dynamometer used, we apply Hooke’s law: Fcont = F = k * Δx and k = F / Δx.
Values of variables: F – tensile force (F = 4 N); Δx – spring elongation (Δx = 5 mm; in SI system Δx = 5 * 10-3 m).
Let’s make a calculation: k = F / Δx = 4 / (5 * 10-3) = 800 N / m.
Answer: The spring rate is 800 N / m.
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