The dynamometer spring with a stiffness of 40 N / m is stretched with a force of 4 N. What work was performed during this?

To determine the work performed when the spring of the taken dynamometer is stretched, we apply the formula: A = ΔEp = k * Δx ^ 2/2 = k * (F / k) ^ 2/2 = F ^ 2 / 2k.

Variables: k is the stiffness of the dynamometer spring (k = 40 N / m); F – tensile force (F = 4 N).

Let’s make a calculation: A = 4 ^ 2 / (2 * 40) = 0.2 J.

Answer: When the spring of the taken dynamometer was stretched, a work of 0.2 J.