The echo of the sound sent by the echo sounder into the reservoir, the person heard after 4 seconds.

The echo of the sound sent by the echo sounder into the reservoir, the person heard after 4 seconds. What is the depth of the reservoir? The speed of sound in water should be taken equal to 1450 m / s

t = 4 s.

Vsv = 1450 m / s.

H -?

The sound sent by the echo sounder reaches the bottom of the reservoir and, reflected from it, returns back to it. The sound in the reservoir travels a distance S equal to two depths of the reservoir: S = 2 * H.

According to the definition, the speed of sound propagation Vsv is determined by the formula: Vsv = S / t = 2 * H / t.

2 * H = Vev * t.

The depth of the reservoir H will be determined by the formula: H = Vsc * t / 2.

H = 1450 m / s * 4 s / 2 = 2900 m.

Answer: the depth of the reservoir is H = 2900 m.