The edge of one cube is 4 times the edge of the second. How many times: 1) the surface area of the first cube

| June 14, 2021 | education

The edge of one cube is 4 times the edge of the second. How many times: 1) the surface area of the first cube is greater than the surface area of the second; 2) the volume of the first cube is greater than the volume of the second

Let us denote the edge of the second cube by a. Then the edge of the first cube is 4a.

The surface area of the second cube is sought to be S = 6 * a² = 6а².

The surface area of the first cube will be: S = 6 * (4a) ² = 6 * 16 * a² = 96а².

Let’s find how much more the surface area.

96а² ÷ 6а² = 6.

The volume of the second cube is V = a³.

Then the volume of the first cube is V = (4a) ³ = 64a³.

Let’s find how many times the volume is.

64a³ ÷ a³ = 64.

Answer: the surface area of the first cube is 16 times larger, and the volume is 64 times larger.



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