The efficiency of a certain heat engine is 25%. What is its useful work if the amount of heat it receives is 80kJ?
| April 19, 2021 | education
Initial data: η (efficiency of some heat engine) = 25% = 0.25; Q (amount of heat received by the heat engine) = 80 kJ.
The useful work of this heat engine is determined from the formula: η = A / Q, whence A = η * Q.
Let’s calculate: A = 0.25 * 80 = 20 kJ.
Answer: The useful work of a certain heat engine will be equal to 20 kJ.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
