The efficiency of an ideal heat engine is 40%. To make the efficiency equal to 60%, the heater
| September 27, 2021 | education
The efficiency of an ideal heat engine is 40%. To make the efficiency equal to 60%, the heater temperature must be increased by …
These tasks: η1 (initial efficiency of the heat engine) = 40% (0.4); η2 (required efficiency of the heat engine) = 60% (0.6).
1) Let us express the constant temperature of the refrigerator: η1 = 1 – Тх / Тн1; 0.4 = 1 – Tx / Tn1; Tx / Tn1 = 0.6 and Tx = 0.6 * Tn1.
2) Determine the required heater temperature: η2 = 1 – Тх / Тн2; 0.6 = 1 – Tx / Tn2; Tx / Tn2 = 0.4 and Tn2 = Tx / 0.4 = 0.6 * Tn1 / 0.4 = 1.5Tn1.
Answer: The temperature of the heater will need to be increased by 1.5 times.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
