The efficiency of the heat engine is 30%. This means that when the energy Q is released during

univerkov | September 9, 2021 | education

The efficiency of the heat engine is 30%. This means that when the energy Q is released during the combustion of fuel, an energy equal to?

Coefficient of performance (COP) is the ratio of useful work to perfect work.

(Qpol / Qsatr) * 100% = efficiency.

Or in Russian to say this is the percentage of useful work (in our case, 30%) to all the work spent (in any case, it is equal to 100%).

For the perfect work is taken – 1.

Qpol = (efficiency * Qzatr) / 100%,

Qpol = (30 * 1) / 100 = 0.3,

Answer: 0.3Q so much energy is spent on doing useful work.

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