The elasticity factor of the rubber cord is 1000 N / m. Determine the potential energy of the cord when its elongation is 6 cm.

Given: k = 1kN / m = 10 ^ 3 N / m, x = 6cm = 0.06 meters
Find: Ep -?
Decision:
Ep = kx ^ 2/2
Ep = 10 ^ 3 N / m * 0.06m ^ 2/2 = 1.8 J.



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