The electric boiler has a current consumption of 20 amps. how much heat will be released

The electric boiler has a current consumption of 20 amps. how much heat will be released from its spiral in 1.5 hours if it is included in a 220 volt circuit.

According to the condition of the problem, we were given the current strength I = 20A, the voltage U = 220V and the operating time of the boiler t = 1.5 hours.

First, we find the power of the boiler. Where P is the power.

P = U * I = 20a * 220v = 4400Wt.

Now, knowing the power and time, you can find the heat released by the boiler. Only the power is given in kilowatts.

P = 4400Wt = 4.4KWt.

And now we find the desired heat from the formula.

A = P * t = 4.4KBt * 1.5h = 6.6KJ * h.

The answer was 6.6 kilojoules * hour.