The electric charges of the two clouds are respectively equal to 10 C and -30 C.

The electric charges of the two clouds are respectively equal to 10 C and -30 C. The average distance between clouds is 15 km. With what force do the clouds interact?

Task data: r (average distance between these clouds) = 15 km (15 * 10 ^ 3 m); q1 (electric charge of the first cloud) = 10 C; q2 (charge of the second cloud) = -30 Cl.

Reference values: k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2.

The formula for calculating the force of interaction between two given clouds: F = k * | q1 | * | q2 | / r ^ 2.

Let’s perform the calculation: F = 9 * 10 ^ 9 * | 10 | * | -30 | / (15 * 10 ^ 3) ^ 2 = 12,000 N (12 kN).

Answer: These clouds interact with a force of 12 kN.